Abhinay Sir Maths Class Notes And Book PDF 2022

Abhinay Sir Maths Class Notes And Book PDF 2022

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Abhinay Sir Maths Class Notes Questions Answers

1. 121 Divided by 11 is 

1. 11

2. 10

3. 19

4. 18

Answer: a

 

2. 60 Times of 8 Equals to

1. 480

2. 300

3. 250

4. 400

Answer: a

 

3. Find the Missing Term in Multiples of 6 : 6, 12, 18, 24, _, 36, 42, _ 54, 60.

1. 32, 45

2. 30, 48

3. 24, 40

4. 25, 49

Answer: b

 

4. What is the Next Prime Number after 7 ?

1. 13

2. 12

3. 14

4. 11

Answer: d

 

5. The Product of 131 × 0 × 300 × 4

1. 11

2. 0

3. 46

4. 45

Answer: b

 

6. Solve 3 + 6 × ( 5 + 4) ÷ 3 – 7

1. 11

2. 16

3. 14

4. 15

Answer: c

 

7.  Solve 23 + 3 ÷ 3

1. 24

2. 25

3. 26

4. 27

Answer: a

 

8. What is 6% Equals to

1. 0.06

2. 0.6

3. 0.006

4. 0.0006

Answer: a

 

9. How Many Years are there in a Decade?

1. 5 years 

2. 10 years

3. 15 years

4. 20 years

Answer: b

 

10. How Many Months Make a Century?

1. 12

2. 120

3. 1200

4. 12000

Answer: c, 1200 months. As a century has a total of 100 years and each year has a total of 12 months, then a century will have a sum of 1200 months in it (100 × 12 = 1200 months).

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Abhinay Sir Maths Class Notes Questions

1. Which is greater than 4?

(a) 5,

(b) -5,

(c) -1/2,

(d) -25.

Solution:5 greater than 4.
Answer: (a)

2. Which is the smallest?

(a) -1,

(b) -1/2,

(c) 0,

(d) 3.

Solution:The smallest number is -1.
Answer: (a)

3. Combine terms: 12a + 26b -4b – 16a.

(a) 4a + 22b,

(b) -28a + 30b,

(c) -4a + 22b,

(d) 28a + 30b.

Solution:12a + 26b -4b – 16a.

= 12a – 16a + 26b – 4b.

= -4a + 22b.

Answer: (c)

4. Simplify: (4 – 5) – (13 – 18 + 2).

(a) -1,

(b) –2,

(c) 1,

(d) 2.

Solution:(4 – 5) – (13 – 18 + 2).

= -1-(13+2-18).

= -1-(15-18).

= -1-(-3).

= -1+3.

= 2.

Answer: (d)

5. What is |-26|?

(a) -26,

(b) 26,

(c) 0,

(d) 1

Solution:|-26|= 26.

Answer: (b)

6. Multiply: (x – 4)(x + 5)

(a) x² + 5x – 20,

(b) x² – 4x – 20,

(c) x² – x – 20,

(d) x² + x – 20.

Solution:(x – 4)(x + 5).

= x(x + 5) -4(x + 5).

= x² + 5x – 4x – 20.

= x² + x – 20.

Answer: (d)

7. Factor: 5x² – 15x – 20.

(a) 5(x-4)(x+1),

(b) -2(x-4)(x+5),

(c) -5(x+4)(x-1),

(d) 5(x+4)(x+1).

Solution:5x² – 15x – 20.

= 5(x² – 3x – 4).

= 5(x² – 4x + x – 4).

= 5{x(x – 4) +1(x – 4)}.

= 5(x-4)(x+1).

Answer: (a).

8. Factor: 3y(x – 3) -2(x – 3).

(a) (x – 3)(x – 3),

(b) (x – 3)²,

(c) (x – 3)(3y – 2),

(d) 3y(x – 3).

Solution:3y(x – 3) -2(x – 3).

= (x – 3)(3y – 2).

Answer: (c).

9. Solve for x: 2x – y = (3/4)x + 6.

(a) (y + 6)/5,

(b) 4(y + 6)/5,

(c) (y + 6),

(d) 4(y – 6)/5.

Solution:2x – y = (3/4)x + 6.

or, 2x – (3/4)x = y + 6.

or, (8x -3x)/4 = y + 6.

or, 5x/4 = y + 6.

or, 5x = 4(y + 6).

or, 5x = 4y + 24.

or, x = (4y + 24)/5.

Therefore, x = 4(y + 6)/5.

Answer: (b).

10. Simplify:(4x² – 2x) – (-5x² – 8x).

Solution:(4x² – 2x) – (-5x² – 8x)

= 4x² – 2x + 5x² + 8x.

= 4x² + 5x² – 2x + 8x.

= 9x² + 6x.

= 3x(3x + 2).
Answer: 3x(3x + 2)

11. Find the value of 3 + 2 • (8 – 3)

(a) 25,

(b) 13,

(c) 17,

(d) 24,

(e) 15.

Solution:3 + 2 • (8 – 3)

= 3 + 2 (5)

= 3 + 2 × 5

= 3 + 10

= 13

Answer: (d)

12. Rice weighing 3³/₄ pounds was divided equally and placed in 4 containers. How many ounces of rice were in each?

Solution:3³/₄ ÷ 4 pounds.

= (4 × 3 + 3)/4 ÷ 4 pounds.

= 15/4 ÷ 4 pounds.

= 15/4 × 1/4 pounds.

= 15/16 pounds.

Now we know that, 1 pound = 16 ounces.

Therefore, 15/16 pounds = 15/16 × 16 ounces.

= 15 ounces.

Answer: 15 ounces.

13. Factor: 16w³ – u⁴w³
Solution:16w³ – u⁴w³.

= w³(16 – u⁴).

= w³(4² – ((u²)²).

= w³(4 + u²)(4 – u²).

= w³(4 + u²)(2² – u²).

= w³(4 + u²)(2 + u)(2 – u).

Answer: w³(4 + u²)(2 + u)(2 – u).

14. Factor: 3x⁴y³ – 48y³.
Solution:3x⁴y³– 48y³.

= 3y³(x⁴ – 16).

= 3y³[(x²)² – 4²].

= 3y³(x² + 4)(x² – 4).

= 3y³(x² + 4)(x² – 2²).

= 3y³(x² + 4)(x + 2)(x -2).

Answer: 3y³(x² + 4)(x + 2)(x -2)

 

15. What is the radius of a circle that has a circumference of 3.14 meters?

Solution:
Circumference of a circle = 2πr.

Given, circumference = 3.14 meters.

Therefore,

2πr = Circumference of a circle

or, 2πr = 3.14.

or, 2 × 3.14r = 3.14,[Putting the value of pi (π) = 3.14].

or, 6.28r = 3.14.

or, r = 3.14/6.28.

or, r = 0.5.

Abhinay Sir Maths Class Notes PDF Download

Chapter Name	Download Link
Number System by Abhinay Sir (अभिनय सर संख्या पद्धति)	Download
Average by Abhinay Sir (अभिनय सर औसत)	Download
Time, Speed, Distance by Abhinay Sir (अभिनय सर समय, दूरी, चाल)	Download
Time and Work by Abhinay Sir (अभिनय सर समय तथा काम)	Download
Simple Interest by Abhinay Sir (अभिनय सर साधारण ब्याज)	Download
LCM & HCF by Abhinay Sir (अभिनय सर लoसo,मoसo)	Download
Compoud Interest by Abhinay Sir (अभिनय सर चक्रवृद्धि ब्याज)	Download
Geometry by Abhinay Sir (अभिनय सर ज्यामिति)	Download
Co-ordinate Geometry by Abhinay Sir (अभिनय सर निर्देशांक ज्यामिति	Download
Percentage by Abhinay Sir (अभिनय सर प्रतिशतता)	Download
Algebra by Abhinay Sir (अभिनय सर बीजगणित)	Download
Profit & Loss by Abhinay Sir (अभिनय सर लाभ और हानि)	Download
Trigonometry by Abhinay Sir (अभिनय सर त्रिकोणमिति)	Download
Partnership by Abhinay Sir (अभिनय सर साझेदारी)	Download
Mixure & Alligation by Abhinay Sir (अभिनय सर मिश्रण)	Download

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