# Ratio and Proportion Questions with Solutions PDF

## Ratio and Proportion Questions with Solutions PDF

Hello Students,

Download Ratio and Proportion Question with Solution PDF. Profit and Loss Question PDF for SSC, Railway Exam.  Welcome to the Lets Study Together online Free PDF section. As we all know in many competitive exams like SSC, Railways, Banking, FCI, CWC, Insurance Exams, UPSC, and other state PCS exams, Ratio and Proportion Questions asked repeatedly, so you cannot ignore the Ratio and Proportion section of Quantitative Aptitude.

Today we have compiled “450+ Ratio and Proportion Question Free PDF with Solution for SSC, Railway & Banking Exam”. You can download the Free PDF with Solution so that you get all the important questions at one place. And it will become very easy for you guys to revise them.

As questions are based on previous year papers, there are chances that candidates will find many questions from the Ratio and Proportion Questions PDF in all competitive Exams. If you check the last 4-5 year’s papers of SSC CGL any other competitive exams, you will find that many questions from Ratio and Proportion are asked. You can download Ratio and Proportion Question Free PDF with Solution for SSC, Railways, UPSC, and State PCS from the below link-

### Sample Questions of Ratio and Proportion

Q.: In a cricket match there are three types of tickets say A, B and C each costing ₹ 1000,₹ 500 and ₹ 200 respectively. The ratio of the ticket sold of category A, B and C is 3 : 2 : 5. If the total collection from selling the tickets is ₹ 2.5 crore. Find the total number of tickets sold.
a) 50000
B) 40000
c) 45000
d) 60000

Ans : 50000
Sold tickets of A,B,C categories are 3x, 2x, and 5x respectively.
Total Collection = $(3x \times 1000)+(2x \times 500)+(5x \times 200) = 25000000$
5000x = 25000000
x = 5000
Total sold tickets = 3x+2x+5x = 10x = 50000

Q.: The ratio of the length of a school ground to its width is 5 : 2. If the width is 40 m, then the length is :
a) 200 m
b) 100 m
c) 50 m
d) 80 m

Ans : b) 100 m
Length : Breadth = 5 : 2,
Length : 40 = 5 : 2,
L x 2 = 40 x 5, L = 100 m

Q.: बैग x, तथा बैग y में गेंदों की संख्या का अनुपात 2:3 है। बैग y से पांच गेंदें ली जाती हैं और बैग x में गिरा दी जाती हैं। अब प्रत्येक थैले में गेंदों की संख्या बराबर है। अब प्रत्येक बैग में गेंदों की संख्या कितनी है:
a) 45
b) 20
c) 30
d) 25

Ans : b) 20
बैग x और y में क्रमशः गेंदों की संख्या = 2a और 3a
3ए – 5 = 21 + 3, ए = 8
गेंदों की कुल संख्या = 5 a = 40
प्रत्येक बैग में गेंदें = 20

Q.: दूध और पानी के 45 लीटर मिश्रण में दूध का पानी से अनुपात 2:1 है. जब मिश्रण में कुछ मात्रा में पानी मिला दिया जाता है, तो यह अनुपात 1:2 हो जाता है. मिलाए गए पानी की मात्रा है:
a) 10 Liters
b) 21 Liters
c) 35 Liters
d) 45 Liters

Ans : d) 45 Liters
दूध : पानी : 2 : 1 = 30: 15
माना x Ltrs पानी मिलाने से अनुपात 1:2 हो जाता है
30 : (15+x) = 1 : 2
=> 15 + x = 60, x =45 Liters

### Ratio and Proportion Questions Answers

• The 1st 3 terms of a proportion are 3, 9 and 12. The 4th term is:
A. 18
B. 24
C. 30
D. 36

• D. 36

Explanation:

• (9*12)/3 = 36

• A store owner is packing small radios into larger boxes that measure 25 * 42 * 60 inches. If the measurement of each radio is 7 * 6 * 5 inches, then how many radios can be placed in the box?
A. 260
B. 300
C. 340
D. 380

• B. 300

Explanation:

Total no’s of radios can be placed in the box (25 * 42 * 60) / (7 *6 * 5) = 6300 / 210 = 300
• 6 years ago, the ratio of the ages of Kunal and Sagar was 6:5. 4 years hence, the ratio of their ages will be 11:10. What is Sagar’s age at present?
A. 12 years
B. 14 years
C. 16 years
D. 18 years

• C. 16 years

Explanation:

• Let the ages of Kunal and sagar be x and y respectively.

• According to the equation, (x-6)/(y-6) = 6/5

• => (x+4)/(y+4) = 11/10

• After solving we get y = 16

• If 40% of a number is equal to 2/3rd of another number, what is the ratio of 1st number to the 2nd number?
A. 2 : 5
B. 3 : 7
C. 5 : 3
D. 7 : 3

• C. 5 : 3

Explanation:

• Let 40% of A = 2/3 B. Then,

• 40A/100 = 2B/3 => 2A/5 = 2B/3

• A/B = (2/3 * 5/2) = 5/3

Hence, A : B = 5 : 3
• A gardener wants to plant trees in his garden in rows in such a way that the number of trees in each row to be the same. If there are 24 rows the number of trees in each row is 42. If there are 12 more rows find the number of trees in each row?
A. 24 trees
B. 28 trees
C. 32 trees
D. 36 trees

• B. 28 trees

Explanation:

• Required number of trees = 24/36 * 42 = 28

• The inverse ratio of 3 : 2 : 1 is?
A. 1 : 2 : 3
B. 2 : 3 : 1
C. 3 : 1 : 2
D. 2 : 3 : 6

• D. 2 : 3 : 6

Explanation:

• 1/3 : 1/2 : 1/1 = 2 : 3 : 6

• If a:b = 4:1, then find (a – 3b) / (2a – b)?
A. 1/7
B. 2/7
C. 3/7
D. 5/7

• A. 1/7

Explanation:

• a/b = 4/1 => a = 4b

• (a – 3b) / (2a – b) = (4b – 3b) / (8b – b)

= b/7b => 1/7
• The ratio of the incomes of Chetan and Dinesh is 3:4. The ratio of their expenditures is 5:7. If each of them saves Rs.200, find the incomes of both?
A. Rs.600, Rs.800
B. Rs.1200, Rs.1600
C. Rs.1500, Rs.2000
D. Rs.1800, Rs.2400

• B. Rs.1200, Rs.1600

Explanation:

• The savings of Chetan and Dinesh are 3x – 5y and 4x – 7y respectively.

• 3x – 5y = 200 — (1)

• 4x – 7y = 200 — (2)

• Multiplying (1) by 7 and (2) by 5 and subtracting the resultant equation (2) from resultant equation (1), we get x = 400.

• The incomes of Chetan and Dinesh are 3x = Rs.1200 and 4x = Rs.1600 respectively.

• A and B together have Rs. 1210. If 4/15 of A’s amount is equal to 2/5 of B’s amount, how much amount does B have?
A. Rs. 460
B. Rs. 484
C. Rs. 550
D. Rs. 664

• B. Rs. 484

Explanation:

• 4/15 A = 2/5 B

• =>A = (2/5 * 15/4) B

• =>A = 3/2 B

• =>A/B = 3/2

• A : B = 3 : 2

• Therefore B’s share = Rs. (1210 * 2/5) = Rs. 484

• Two numbers are respectively 20% and 50% more than a third number. The ratio of the two numbers is:
A. 2 : 5
B. 3 : 5
C. 4 : 5
D. 6 : 7

• C. 4 : 5

Explanation:

• Let the third number be x

• Then, first number = 120% of x = 120x/100 = 6x/5

• Second number = 150% of x = 150x/100 = 3x/2

• Ratio of first two numbers = 6x/5 : 3x/2 = 12x : 15x = 4 : 5