Time And Work Formula PDF Download

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Time And Work Formula PDF Download

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Time and Work Formula :- In the exams which have been conducted nowadays, at least one question is being asked directly on Time and Work Formula PDF, Time and Work Formula, so it becomes important that you read Time and Work Formula PDF in Hindi. , Time and Work Formula For SSC CGL Cover the entire topic properly so that if any twisted question is asked, you will be able to answer it easily. Now we read the complete information related to Time and Work Formula and Tricks through the points given below.

Time and work aptitude questions are asked in every competitive exam. Placement papers for TCS, Infosys, Wipro, CTS, HCL, IBM or Bank exam or MBA exams like CAT, XAT, MAT, or other exams like GRE, GMAT tests always contain one or more aptitude questions from this section of quantitative aptitude. Problems on time and work which appear in CAT exams are quite advanced and complicated – But they can be solved easily if you know the basic formulas, shortcuts and tricks.

Time and Work Formulas SSC Notes PDF

Our Compound Interest notes covers all important topic of SSC Mathematics PDF that asked in the examination. One Question must come from Compound Interest formula in Hindi. As you know that we always share for you best and selected ssc study material free of cost.

We share with you Best Handwritten Maths Notes PDF, Mathematics Notes PDF.  We provide time and work problems with solutions in Hindi. Download time and work problems with solutions pdf and boost your preparation. We share SSC CGL time and work solved problems and SSC CHSL time and work problems tricks in Hindi.

Here we provide completet details of Time and Work Formula Indiabix, Time and Work Formula Class 8, Time and Work Formula in Hindi, Time and Distance Formula, Time and Work Tricks, Time and Work Efficiency Formula.

This section will provide shortcuts, tips and tricks to solve quantitative aptitude questions on time and work. These are similar to time and distance shortcuts or ratio and proportion shortcuts. So, all you have to do is be thorough with the basics and practice as many questions as you can.

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Formula’s for Work and Time

Work from Days:

If A can do a piece of work in n days, then A’s one day work = \frac{1}{n}

Days from work:

If A’s one day work = \frac{1}{n}, then A can finish the work in n days

Work Done by A and B

A and B can do a piece of work in ‘a’ days and ‘b’ days respectively.

When working together they will take \frac{ab}{a+b} days to finish the work

In one day, they will finish ( \frac{a+b}{ab})^{th}  part of work.


If A is thrice as good a workman as B, then:

Ratio of work done by A and B = 3: 1.

Ratio of times taken by A and B to finish a work = 1: 3


Efficiency is inversely proportional to the

Time taken when the amount of work done is constant.

Efficiency α = \frac{1}{Time  Taken}


Basic Rules for Work and Time

Rule 1: If A completes a piece of work in x days. And B can completes same piece of work in y days .


One day work of A = \frac{1}{x} One day work of B = \frac{1}{y}

Work done by A + B = \frac{1}{x} + \frac{1}{y} = \frac{x+y}{xy}

Total time = \frac{xy}{x + y}

Rule 2: If A completes a piece of work in x days. B completes same piece of work in y days .C completes same piece of work in z days


One day work of A = \frac{1}{x}

One day work of B = \frac{1}{y}

One day work of C = \frac{1}{z}

Work done by A + B + C = \frac{1}{x} + \frac{1}{y} + \frac{1}{z} = \frac{yz+xz+xy}{xyz}

Total time = \frac{xyz}{xy + yz + zx}.

Rule 3:  If M1 men can complete a work W1 in D1 days and M2 men can complete a work W2 in D2 days then\frac{M_{1}D_{1}}{W_{1}} = \frac{M_{2}D_{2}}{W_{2}}  .

If Time required by Both M1 and M2 is T1 and T2 respectively, then relation is \frac{M_{1}D_{1}T_{1}}{W_{1}} = \frac{M_{2}D_{2}T_{2}}{W_{2}}

Rule 4:  If A alone can complete a certain work in ‘x’ days and A and B together can do the same amount of work in ‘y’ days,

Work done by b =\frac{1}{y} – \frac{1}{x} = \frac{x-y}{xy}

Then B alone can do the same work in \frac{xy}{(x-y)} days

Rule 5: If A and B can do work in ‘x’ days.

If B and C can do work in ‘y’ days.

If C and A can do work in ‘z’ days.

Work done by A,B and C = \left ( \frac{1}{2}\right )\left ( \frac{1}{x}+\frac{1}{y}+\frac{1}{z} \right )

Total time taken when A, B, and C work together \frac{2xyz}{ ( xy+yz+zx )}

Rule 6: Work of one day = \frac{Total  work}{Total  number  of  working  days}

Total work = one day work × Total number of working days

Remaining work =  1 – work done

Work done by A = A’s one day work × Total number of working days of A

Rule 7:If A can finish \frac{m}{n} part of the work in D days.

Then total time taken to finish the work by A = \frac{D}{\frac{m}{n}} = \frac{n}{m} × D days

Rule 8:

If A can do a work in ‘x’ days

B can do the same work in ‘y’ days

When they started working together, B left the work ‘m’ days before completion then total time taken to complete the work = (y+m)x/(x+y)

Rule 9: A and B finish work in a days.

They work together for ‘b days and then A or B left the work.

B or A finished the rest of the work in ‘d’ days.

Total time taken by A or B alone to complete the work = \frac{ad}{a – b} or \frac{bd}{a-b}

Time & Work – Sample Questions

All the hard work can go in vain if the candidate does not solve questions based on time and work on a regular basis and try using the different formulas to crack the solution for each question in an even shorter time span.

So, discussed below are a few time and work questions to give an idea as to what type of questions are asked in the competitive exam and what format and pattern is used for the same. 

Q 1. A builder appoints three construction workers Akash, Sunil and Rakesh on one of his sites. They take 20, 30 and 60 days respectively to do a piece of work. How many days will it take Akash to complete the entire work if he is assisted by Sunil and Rakesh every third day?

  1. 10 days
  2. 15 days
  3. 25 days
  4. 30 days
  5. 45 days

Answer: (2) 15 days


Total work done by Akash, Sunil and Rakesh in 1 day = {(1/20) + (1/30) + (1/60)} = 1/10

Work done along by Akash in 2 days = (1/20) × 2 = 1/10

Work Done in 3 days (1 day of all three together + 2 days of Akash’s work) = (1/10) + (1/10) = 1/5

So, work done in 3 days = 1/5

Time taken to complete the work = 5×3 = 15 days

Q 2. To complete a piece of work, Samir takes 6 days and Tanvir takes 8 days alone respectively. Samir and Tanvir took Rs.2400 to do this work. When Amir joined them, the work was done in 3 days. What amount was paid to Amir?

  1. Rs. 300
  2. Rs. 400
  3. Rs. 800
  4. Rs. 500
  5. Rs. 100

Answer: (1) Rs.300


Total work done by Samir and Tanvir = {(1/6) + (1/8)} = 7/24

Work done by Amir in 1 day = (1/3) – (7/24) = 1/24

Amount distributed between each of them =  (1/6) : (1/8) : (1/24) = 4:3:1

Amount paid to Amir = (1/24) × 3 × 2400 = Rs.300

Q 3. Dev completed the school project in 20 days. How many days will Arun take to complete the same work if he is 25% more efficient than Dev? 

  1. 10 days
  2. 12 days
  3. 16 days
  4. 15 days
  5. 5 days

Answer: (3) 16 days


Let the days taken by Arun to complete the work be x

The ratio of time taken by Arun and Dev = 125:100 = 5:4

5:4 :: 20:x

⇒ x = {(4×20) / 5}

⇒ x = 16

Q 4. Time taken by A to finish a piece of work is twice the time taken B and thrice the time taken by C. If all three of them work together, it takes them 2 days to complete the entire work. How much work was done by B alone?

  1. 2 days
  2. 6 days
  3. 3 days
  4. 5 days
  5. Cannot be determined

Answer: (2) 6 days


Time taken by A  = x days

Time taken by B = x/2 days

Time Taken by C = x/3 days

⇒ {(1/x) + (2/x) + (3/x) = 1/2

⇒ 6/x = 1/2

⇒ x = 12

Time taken by B = x/2 = 12/2 = 6 days

Q 5. Sonal and Preeti started working on a project and they can complete the project in 30 days. Sonal worked for 16 days and Preeti completed the remaining work in 44 days. How many days would Preeti have taken to complete the entire project all by herself? 

  1. 20 days
  2. 25 days
  3. 55 days
  4. 46 days
  5. 60 days

Answer: (5) 60 days


Let the work done by Sonal in 1 day be x

Let the work done by Preeti in 1 day be y

Then, x+y = 1/30 ——— (1)

⇒ 16x + 44y = 1  ——— (2)

Solving equation (1) and (2), 

x = 1/60

y = 1/60

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Time And Work Formula Questions

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